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X^2+166X+1264=0
a = 1; b = 166; c = +1264;
Δ = b2-4ac
Δ = 1662-4·1·1264
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{22500}=150$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(166)-150}{2*1}=\frac{-316}{2} =-158 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(166)+150}{2*1}=\frac{-16}{2} =-8 $
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